Easy does it! The Smart Scholar Method

It is clear that Anil, Brij, Chand etc were given 1, 2, 3 etc plus a tenth of what remained after that. If there were n boys, the nth boy must have received n marbles. Thus the number of marbles Maya had brought must be n^2.

After Anil was given 1, the remainder must be divisible by 10. Therefore n^2 must end in 1.

The only perfect squares that end in 1 are 1 (a trivial solution), 9^2 = 81, 11^2 = 121, 19^2 = 361, 21^2 = 441, 29^2 = 841, etc. Of these, only 81 permits distribution of marble in the manner Maya has done, Thus n = 9.

The last boy’s name should begin with the 9th letter of the alphabet, that is, I and hence must be Indra.

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